Question 388151
{{{(7/x - 2) - (3 - x/x)}}}
Any number divided by itself, like x/x, is 1:
{{{(7/x - 2) - (3 - 1)}}}
3-1 = 2
{{{(7/x - 2) - (2)}}}
-2 - 2 = -4
{{{7/x - 4}}}
To subtract we have to have the same denominator:
{{{7/x - 4(x/x)}}}
{{{7/x - (4/1)(x/x)}}}
{{{7/x - (4x/x)}}}
Now we can subtract:
{{{(7-4x)/x}}}<br>
If the problem was
{{{7/(x-2) - (3-x)/x}}}
then please use parentheses around multiple term numerators, like 3-x, and denominators, like x-2. For example:
7/(x-2) - (3-x)/x