Question 388366
 3x^2-4x+7
Using the following quadratic equation
{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
x=(4+-sqrt[-4^2-4*3*7])/2*3
x=(4+-sqrt[16-84])/6
x=(4+-sqrt-68)/6
x=(4+-8.246i)/6
x=4/6+-8.246i
x=.666+-1.374i ans.