Question 388356
A has coordinates (x1,y1)  B (x2,y2) M (x1+x2/2 , y1+y2/2)
use the distance formula to show that AM= 1/2 AB

A (x1,x2)  B (x2,y2)
M (x1+x2/2 , y1+y2/2)
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AM = sqrt (x1-(x1+x2)/2)^2+(y1-(y1+y2)/2)^2)
AM = sqrt((x1-x2)^2+(y1-y2)^2
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AB= {{{sqrt(((x1-x2)^2+(y1-y2)^2)))}}}
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AM = {{{sqrt((x1-x2)^2+(y1-y2)^2)/4}}}
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AM = 1/2*{{{sqrt((x1-x2)^2+(y1-y2)^2)}}}

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substitute sqrt((x1-x2)^2+(y1-y2)^2) with AB
AM=1/2*AB
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