Question 42322
{{{P(a) = a(1 + r)^(t)}}}
{{{3000000 = 5000(1 + r)^(200)}}}
{{{600 = (1 + r)^(200)}}}
{{{600^(1/200) = 1 + r}}}
{{{600^(1/200) - 1 = r}}}
About 0.0325, so about 3.3%.