<PRE><B>Question 388291</B>
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Use Pythagoras.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ c^2\ =\ a^2\ +\ b^2]


So


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ b^2\ =\ c^2\ -\ a^2]


So


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ b\ =\ \sqrt{49\ -\ 4}]


You can do your own arithmetic.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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