Question 388286
Find the minimum of function f(x) = (x+1)^3 - (x-1)^3 
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f'(x) = 3(x+1)^2 - 3(x-1)^2
3(x+1)^2 - 3(x-1)^2 = 0
(x+1)^2 - (x-1)^2 = 0
{{{x^2 + 2x + 1 - x^2 + 2x - 1 = 0}}}
4x = 0
Min at x = 0
f(0) = 2
Minimum at (0,2)