Question 388254
Let {{{x}}} be the number of years since 1998.
So in 1998, {{{x=0}}}.
{{{y=ab^0=92000}}}
{{{a=92000}}}
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In 2005, {{{x=7}}}.
{{{y=92000b^7=220000}}}
{{{b^7=2.391304}}}
{{{b=1.1326}}}
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{{{highlight(y=92000(1.1326)^x)}}}, where {{{x}}} is the number of years since 1998.