Question 388261
I'm assuming you mean {{{4x+y-2=0}}}
A parallel line would have the same x,y relationship but a different constant.
{{{4x+y-a=0}}}
Use the point (4,-3) to solve for the constant, {{{a}}}.
{{{4(4)+(-3)-a=0}}}
{{{a=16-3}}}
{{{a=13}}}
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{{{highlight(4x+y-13=0)}}}