Question 388245
Let x=original ticket price

720/x= number of tickets originally


Equation is based upon NEW ticket price times NEW number of tickets = 720

(x+2)(720/x - 4)=720
720 - 4x +1440/x - 8 = 720
-4x +1440/x - 8 = 0

-4x^2+1440 -8x=0
x^2 +2x -360=0
(x+20)(x-18)=0
x=-20 reject
x=$18 = Original Ticket Price
x+2= $20 = New Ticket Price


Check:  

Number of tickets originally =40

Number of tickets after dropouts = 36


18*40 = 20*36 = $720


Nice Problem!!!


Dr. Robert J. Rapalje, Retired
Seminole State College of Florida