Question 388196
Simplify first,
{{{(xy^2)/(x^2y)=x^(1-2)y^(2-1)=x^(-1)y^(1)=y/x}}}
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So then,
{{{((xy^2)/(x^2y))/(x/y^3)=(y/x)*(y^3/x)}}}
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{{{((xy^2)/(x^2y))/(x/y^3)=highlight(y^4/x^2)}}}