Question 388086
Note: The probability of x successes in n trials is: 
P = nCx* {{{p^x*q^(n-x)}}} where p and q are the probabilities of success and failure respectively. In this case p = 1/6 and q = 5/6 
nCx = {{{n!/(x!(n-x!))}}}
P(0 successes out of five rolls) = (5/6)^5 = .4019