Question 388089
Note: The probability of x successes in n trials is: 
P = nCx* {{{p^x*q^(n-x)}}} where p and q are the probabilities of success and failure respectively. In this case p = 1/6 and q = 5/6 
nCx = {{{n!/(x!(n-x!))}}}
P(2 successes out of five rolls) = 10(1/6)^2(5/6)^3 = .1608