Question 388041
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Hi,
radius = -2 -(-8) = 6   Using points Pt(-8,-4) and center Pt(-2,-4)
 Standard Form of an Equation of a Circle is {{{(x-h)^2 + (y-k)^2 = r^2}}}
where Pt(h,k) is the center and r is the radius 
 (x+2)^2 + (y+4)^2 = 6^2      
{{{drawing(500,500, -15,15,-15,15,grid(1),circle(-2,-4,6), circle(-2,-4,.4),circle(-2,2,.4), circle(-8,-4,.4), circle(4,-4,.4))}}}