Question 388014
{{{368640=90*2^(kt)}}}
where
{{{180=90*2^(k(30))}}}
{{{2=2^(30k)}}}
{{{30k=1}}}
{{{k=1/30}}}
So then,
{{{2^(t/30)=4096}}}
{{{2^(t/30)=2^12}}}
{{{t/30=12}}}
{{{highlight(t=360)}}}minutes