Question 388029
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Hi,         
Standard Form of an Equation of a Circle is {{{(x-h)^2 + (y-k)^2 = r^2}}}
where Pt(h,k) is the center and r is the radius
x^2+y^2-10x+4y+4=0
completing the squares to put into the standard form
x^2 -10x + y^2 +4y + 4 = 0
(x-5)^2 -25 + (y +2)^2 - 4 + 4 = 0
  (x-5)^2 + (y+2)^2 = 25
Center is (5,-2) radius = 5
{{{drawing(500,500, -10,15,-15,10,grid(1),circle(5,-2,5), circle(5,-2,.15)) )}}}