Question 42239
Use this form: {{{y = a(b^x)}}}
{{{y = a(b^x)}}} use (0,-2)
{{{-2 = a(b^0)}}} anything to the zero power is one except for zero
{{{-2 = a}}}
so ....
{{{y = -2(b^x)}}}
{{{-50 = -2(b^2)}}} use (2,-50)
{{{25 = (b^2)}}}
{{{5 = b}}}
so ....
{{{y = -2((5)^x)}}}
so ....
{{{y = -2((5)^(-2))}}}
{{{y = -2(1/(5)^(2))}}}
{{{y = -2(1/(25))}}}
{{{y = -2/25}}}