Question 387834
  <pre><font size = 3 color = "indigo"><b>
Hi,         
 log(7x+1)-log(x-2)= 1
*[tex \LARGE\ \ log_bx - log_by = log_b(x/y) ]
*[tex \LARGE\ \ log (7x+1) - log (x-2) = log (7x+1)/(x-2)= 1 ]
*[tex \LARGE \ \ \ \ \ \ \ \ \ \ log_b(x) \ = \ y \ \ \Rightarrow\ \ b^y = x]
  10^1 = (7x+1)/(x-2)
  10(x-2) = 7x+1
  10x -20 = 7x + 1
       3x = 21
        x = 7