Question 387761
Recall that the sum (S) of an infinite geometric series with first term, {{{a[1]}}}, and common ratio, r,is given by:
{{{S = a[1]/(1-r)}}} Here, {{{a[1] = 120}}} and {{{r = 1/2}}} so...
{{{S = 120/(1-1/2)}}}
{{{S = 120/(1/2)}}}
{{{S = 120*2}}}
{{{S = 240}}}