Question 387632
{{{x^2 + y^2 - 2x = x^2 + y^2 - 2x + 1 - 1 = (x - 1)^2 + y^2 - 1}}}.  Now {{{(x - 1)^2 + y^2}}} is smallest when x = 1 and y = 0 (where the value of the expression is -1).  (1,0) is the ordered pair.