Question 387632
x^2 + y^2 - 2x 
any number greater than or less than zero for y will make y^2 greater than zero so y must be zero.
x^2-2x has a minimum at -b/2a
-(-2)/2 = 1
(1,0) Answer
 x^2 + y^2 - 2x = -1 at (1,0)
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Ed