Question 387706
Given the quadratic function f(x) = x2 – 12x + 36, find a value of x such that f(x) = 9.
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f(x) = x^2 – 12x + 36 = 9
{{{x^2 - 12x + 27 = 0}}}
(x-9)(x-3) = 0
x = 3, x = 9