Question 387559
{{{log(2,x) = log(2,x^2-6)}}}
{{{x = x^2-6}}}
{{{0 = x^2-x-6}}}
factoring:
{{{0 = (x-3)(x+2)}}}
x = {-2, 3}
But, testing for extraneous solutions, we throw out the negative solution leaving:
x = 3