Question 387337
I get an answer of 7b^2 - 2b + 8
first you divide 35b^3 by 5b to get 7b^2
then you multiply (5b+5) by 7b^2 to get (35b^3 + 35b^2)
then you subtract (35b^3 + 35b^2) from (35b^3 + 25b^2) to get -10b^2
then you bring down the 30b to get (-10b^2 + 30b)
then you divide -10b^2 by 5b to get -2b
then you multiply (5b+5) by -2b to get (-10b^2 - 10b)
then you subtract (-10b^2 - 10b) from (-10b^2 + 30b) to get 40b
then you bring down the 47 to get (40b + 47)
then you divide 40b by 5b to get 8
then you multiply (5b+5) by 8 to get (40b + 40)
then you subtract (40b + 40) from (40b + 47) to get 7
that's your remainder.


the answer is 7b^2 - 2b + 8 with a remainder of 7


on paper, it looks like what is shown below.


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