Question 387328
{{{6/(z^2+8z+7)+5/(z^2+2z-35)-3/(z^2-4z-5)=0}}}
Factor all the denominators
{{{6/((z+7)(z+1)) + 5/((z+7)(z-5))- 3/((z-5)(z+1))=0}}}
:
The common denominator:(z+7)(z+1)(z-5); multiply each term, results:
6(z-5) + 5(z+1) - 3(z+7) = 0
:
6z - 30 + 5z + 5 - 3z - 21 = 0
Combine like terms
6z + 5z - 3z - 30 + 5 - 21 = 0
:
8z - 46 = 0
:
8z = 46
z = {{{46/8}}} = {{{23/4}}}
:
I did check the math on this but it may be a good idea for you to check it.