Question 387470
 6+2i/6-2i
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(2/2)(3+i)/(3-i)
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= [(3+i)(3+i)]/[(3+i)(3-i)]
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= [9+6i-1]/[9+1]
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= [8+6i]/10
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= [4+3i]/5
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Cheers,
Stan H.