Question 387336
(Binomial Distribution) 
three normal six-sided dice are thrown.find the probability of obtaining
(a) three odd numbers. 
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# of ways to succeed.
There are 3 odd numbers on each die.
# of ways to get three odd #'s = 3^3 = 27
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# of random outcomes = 6^3 = 216
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P(3 odd numbers) = 27/216 = 1/8
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Cheers,
Stan H.