Question 387316
The time the population takes to double remains the same no matter where we pick t. Given this, set t = 0. Then A = 5000e^0 = 5000. Now, set A = 10000 so that we can find t:


{{{10000 = 5000e^(.025t)}}}


{{{2 = e^(.025t)}}}


{{{ln 2 = .025t}}}


{{{t = 40 ln 2}}} = 27.73 (whatever the units of time are)