Question 387296
{{{2sqrt(x)+8=6}}}.  The equation is the same as {{{2sqrt(x) = 6 - 8}}}, or {{{2sqrt(x) = -2}}}, or {{{sqrt(x) = -1}}}.  Incidentally, the quantity {{{sqrt(x)}}} can only be non-negative, and so the last equation has no real solution in x.  It is inconsistent.