<PRE><B>Question 387271</B>
If bus A arrives every 27 minutes and bus B arrives every 15 minutes, and both buses arrive at a stop at 5:07am, what time will they arrive at the same time again?
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Find the least common multiple of 15 and 27.
15 = 3*5
27 = 3^3
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lcm = 3^3*5 = 27*5 = 135 minutes
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5:07 + 135 min = 5:07+ (2hrs 15min) = 7:22 am
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Cheers,
Stan H.
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