Question 387141
The quadratic formula states that, for any second-degree polynomial {{{ax^2 + bx + c = 0}}}, where a, b, and c are coefficients, then


{{{x = (-b +- sqrt(b^2 - 4ac))/2a}}}


In your provided quadratic, a = 1, b = 4, c = 3. Now we just plug in those numbers and simplify:


{{{x = (-4 +- sqrt(4^2 - 4(3)(1)))/2}}}


{{{x = (-4 +- 2)/2}}} --> x = -3 or -1. You can check each solution and see that they satisfy the equation.