Question 387021
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Hi,         
the standard slope-intercept form for an equation of a line: y = mx + b  
where m is the slope and b the y-intercept.  
Line perpendicular to 2x + 7y = -49
2x + 7y = -49
      y = -(2/7)x - 7  slope is (-2/7)
Line perpendicular will have a slope = 7/2  (negative reciprocal)
New Line y = (7/2)x + b
     y = (7/2)x + b  using order pair pt(-7,-5) to solve for b
     -5 = 7/2)*-7 + b
     -100/2 - 49/2 = b
          -149/2 = b
     y = (7/2)x -149/2

  {{{graph( 300, 300,-50,50,-50,50,(-2/7)x-7,(7/2)x - 149/2) }}}