Question 386922
Write the slope-intercept equation for the line that passes through (10, 12) and is perpendicular to 5x + 8y = 1 Please show all of your work.
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passes through (10, 12) and is perpendicular to 5x + 8y = 1 
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5x + 8y = 1 
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-5x 
8y=-5x+1
/8
y=(-5/8)x+(1/8)
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compare with y= mx +b
slope m= -5/8
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perpendicular line will have slope of 8/5.
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passes through (10, 12) slope 8/5
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find b in y = mx+b
12=10*8/5 +b
12=16+b
b=-4
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equation will be
m= 8/5, b =-4
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{{{(highlight(y = (8x/5)-4))}}} is the equation
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{{{graph(300,300,-5,5,-5,5,((-5x/8)+(1/8)),((8x/5)-4)))}}}

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