Question 386773
It's slanted. The side to the far left (looks kind of like a base) is side x. across from the "base" there's a segment, used so that it splits the triangle into one smaller triangle and one smallish quadrilateral. The length of this segment is 8. The top of the quadrilateral is y, the bottom is 4. The top part of the smaller triangle is 5, and the bottom part is 7.
:
If I understand this rightly, the small triangle sides are 8, 5, 7
If this is the case you can find the top angle (opposite the segment) using the law of cosines
a^2 = b^2 + c^2 - 2bc*cos(A)
using the small triangle values
8^2 + 5^2 + 7^2 - 2(5*7)*cos(A)
64 = 74 - 70*cos(A)
70cos(A) = 74 - 64
cos(A) = {{{10/70}}}
A = 81.8 degrees
:
Now is the segment parallel to x, it would help to know that?
If it is you can find y:
{{{5/7}}} = {{{(y+5)/11}}}
:
Then use the law cosines again to find x