<PRE><B>Question 386798</B>
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You didn&#39;t specify a compounding period so I will assume annual.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A\ =\ P\left(1\ +\ r\right)^t]


Plugging in your givens, we get:



*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A\ =\ 2000\left(1\ +\ 0.055\right)^4]


The rest is just punching buttons on your calculator.  Anything more precise than two decimals is silly though -- we are working with money, after all.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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