Question 386539
factor each problem.
1) 6x^4y^5z^2 – 18x^4y^6z^4 + 24x^2y^5z^3
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Note that we can factor out 6, leaving
6(x^4y^5z^2 – 3x^4y^6z^4 + 4x^2y^5z^3)
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We can also factor out x^2 leaving:
6x^2(x^2y^5z^2 – 3x^2y^6z^4 + 4y^5z^3)
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Factor out y^5
6x^2*y^5(x^2*z^2 – 3x^2*y*z^4 + 4z^3)
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And factor out z^2
6x^2*y^5*z^2(x^2 – 3x^2*y*z^2 + 4z)
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:
2) 16x^2 – 9
This is the "difference of squares" which factors to:
(4x - 3)(4x + 3); FOIL this and prove it to yourself