Question 386560
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Hi
Standard Form of an Equation of a Circle is {{{(x-h)^2 + (y-k)^2 = r^2}}}
 (x - 6)^2 + (y + 5)^2 = 152
 Center is Pt(6,-5)  radius is sqrt(152) = 12.38
{{{drawing(500,500, -25,25,-25,25,grid(1),circle(6,-5,12.38), circle(6,-5,.15), locate(6,-5,C))}}}