Question 386513
Use the midpoint formula to find the center, ({{{h}}},{{{k}}})
{{{h=(x[1]+x[2])/2=(-11-3)/2}}}
{{{k=(y[1]+y[2])/2=(-8-2)/2}}}
Use the distance formula to find the diameter, {{{D}}}.
{{{D^2=(x[2]-x[1])^2+(y[2]-y[1])^2}}}
{{{D^2=(-11-(-3))^2+(-8-(-2))^2}}}
{{{D^2=(-11+3)^2+(-8+2)^2}}}
{{{D=sqrt((-11+3)^2+(-8+2)^2)}}}
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Then plug those values into the general equation for a circle centered at ({{{h}}},{{{k}}}) with a diameter, {{{D}}}:
{{{(x-h)^2+(y-k)^2=D^2/4}}}