Question 386507
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Hi,         
*[tex \LARGE\ \ log_5(x+1) - log_5x = log_5 (x+1)/x = 2 ]

*[tex \LARGE \ \ \ \ \ \ \ \ \ \ log_b(x) \ = \ y \ \ \Rightarrow\ \ b^y = x]
   5^2 = (x+1)/x
Solving for x
    25x = x + 1
    24x = 1
      x = 1/24