Question 386468

Convert to slope intercept form,{{{y=mx+b}}}
{{{3y=4x-6}}}
{{{y=(4/3)x-2}}}
Perpendicular lines have slopes that are negative reciprocals,
{{{m[1]*m[2]=-1}}}
{{{(4/3)*m[2]=-1}}}
{{{m[2]=-(3/4)}}}
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{{{y=-(3/4)x+b}}}
Use the point, (-3,0) to solve for {{{b}}}.
{{{0=-(3/4)(-3)+b}}}
{{{b=-9/4}}}
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{{{highlight(y=-(3/4)x-9/4)}}}
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{{{drawing(300,300,-6,6,-6,6,grid(1),circle(-3,0,0.3),graph(300,300,-6,6,-6,6,0,(4/3)x-2,-(3/4)x-9/4))}}}