Question 386472
{{{(-3a^(-2)b^(-3)c^0)^(-2) / (-2a^(4)b^(2)c^(-2))^3=((1/9)a^(4)b^(6)) / (-8a^(12)b^(6)c^(-6))}}}

{{{(-3a^(-2)b^(-3)c^0)^(-2) / (-2a^(4)b^(2)c^(-2))^3=-(1/72)a^(4-12)b^(6-6)c^(6)}}}
{{{(-3a^(-2)b^(-3)c^0)^(-2) / (-2a^(4)b^(2)c^(-2))^3=-(1/72)a^(-8)b^(0)c^(6)}}}
{{{(-3a^(-2)b^(-3)c^0)^(-2) / (-2a^(4)b^(2)c^(-2))^3=highlight(-(c^6/(72a^(8)))))}}}