Question 386384
To graph a linear equation, start by putting the equation into slope-intercept form:
y = mx + b
where m is the slope and b is the y-intercept. 

Your equation is almost in the right form; we just need to reorder the terms on the right hand side:

{{{y=-2-(1/2)x}}}
{{{y = -(1/2)x - 2}}}, or
{{{y = -(1/2)x + (-2)}}}

So, the slope (m) of the line is {{{-(1/2)}}} and the y-intercept is -2
The y-intercept means the line has a y value of -2 when x = 0.
This is enough to draw the line, but to make it easier to draw
we can also find the value of x when y = 0:
{{{0 = -(1/2)x - 2}}}
{{{0 + 2 = -(1/2)x - 2 + 2}}}
{{{2 = -(1/2)x}}}
{{{2*(-2) = -(1/2)*(-2)x}}}
-4 = x

So the x intercept (the value of x when y = 0) is -4.
Now we have two points: 
(-4, 0)
(0, -2)

You can use these two points to draw the following graph:


{{{graph(300, 200, -5, 5, -5, 5, (-1/2)x-2)}}}