Question 386347
Larry drove 250 miles in 2 hours more than it took Terrell to drive 159 miles. Terrell drove at an average rate of 3 miles per hour faster than Larry. How fast did each one travel?
miles per hour (Larry)=

miles per hour (Terrell)=

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larry's rate = x
Terrell x+3
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t=d/r
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Larry's time - Terrell's time = 2 hours
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{{{(250/x)-(159/(x+3))=2}}}

LCD = x(x+3)
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{{{(250(x+3)-159x)/(x(x+3))=2}}}
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{{{(250x+750-159x)/(x^2+3x)=2}}}
multiply by (x^2+3x)
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{{{91x+750)=2(x^2+3x)}}}
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91x+750=2x^2+6x
reorganize the terms
2x^2+6x-91x-750=0
2x^2-85x-750=0
2x^2-100x+15x-750=0
2x(x-50)+15(x-50)=0
(2x+15)(x-50)=0
{{{(highlight(x=50mph))}}} is Larry's rate
{{{(highlight(53mph))}}} is Terrell's rate
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m.ananth@hotmail.ca