Question 386242
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The *[tex \Large y]-coordinate of EVERY point on the graph of *[tex \Large 2y\ =\ 6] is 3.  So pick any two points on the graph that you like, *[tex \Large (x_1,3)] and *[tex \Large (x_2,3)] such that *[tex \Large x_1\ \neq\ x_2].  Then use the slope formula:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ m\ =\ \frac{y_1\ -\ y_2}{x_1\ -\ x_2} ]


where *[tex \Large \left(x_1,y_1\right)] and *[tex \Large \left(x_2,y_2\right)] are the coordinates of the given points.


Fill in the numbers:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ m\ =\ \frac{3\ -\ 3}{x_1\ -\ x_2}\ =\ \frac{0}{x_1\ -\ x_2}]


You can see that the result is zero divided by some arbitrary value that is not zero. So regardless of the points selected the calculated slope will be zero.


And, just an Oh, By The Way, the intercept is NOT 3.  The *[tex \Large y]-coordinate of the *[tex \Large y]-intercept is 3, but the actual *[tex \Large y]-intercept is *[tex \Large (0,3)].  Super Double Plus Extra Credit:  What is the *[tex \Large x]-intercept of this graph? 


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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