Question 386178
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Hi
A random sample of 121 men regarding IQ scores produced a mean of 104 points
with a standard deviation 16 points.
Construct a 98% confidence interval for the mean number of IQ scores.
ME = 2.3263[16/sqrt(121)] = 3.3837
CI: 104-3.3837 < u < 104 + 3.3837