Question 386173
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Hi,         
*[tex \LARGE \ \ \ \ \ \ \ \ \ \ log_b(x) \ = \ y \ \ \Rightarrow\ \ b^y = x]
*[tex \LARGE \ \ \ \ \ \ \ \ \ \ log_5(1/125) \ = \ x \ \ \Rightarrow\ \ 5^x = 1/125]
   5^x = 1/5^3
   5^x = 5^-3
     x = -3