Question 386136
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Hi
Line perpendicular to 4x-2y+2=0  OR y = 2x+1  slope = 2
New line will have a slope = -1/2  (negative reciprocal of 2)
the standard 'slope-intercept form' for an equation of a line: y = mx + b 
 where m is the slope and b the y-intercept.  
y = -.5x + b Using ordered pair Pt(1,4) to solve for b
 4 = -.5*1 + b
 4.5 = b
y = -.5x + 4.5  OR   5x + 10y = 45 (in standard from)
{{{drawing(300,300, -6, 6, -6, 6, grid(1),
circle(0, 1,0.2),
circle(1, 4,0.2),
graph( 300, 300, -6, 6, -6, 6, 2x+1,-.5x + 4.5))}}}