Question 386089
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Hi,         
solving 
{{{((3x+2)/(x-2)) + (1/x) = (-2)/(x^2-2x)}}}
{{{((3x+2)/(x-2)) + (1/x) = (-2)/(x(x-2)))}}}
Multiplying each term by x(x-2) so as all denominators = 1
  x(3x+2) + (x-2) = -2
  3x^2 + 2x + x - 2 = -2
  3x^2 + 3x  = 0
  3x(x+1) = 0
   3x = 0
    x = 0  this solution tossed out as one cannot have zero in the deominator
  (x+1) = 0
    x = -1