Question 386034
A 10-foot ladder is set 6 feet from the base of the wall. How far up the wall will the ladder reach?
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The wall, ground and the ladder forms a "right triangle" (where the hypotenuse is the ladder).
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Let x = distance the ladder will reach on the wall
then
x^2 + 6^2 = 10^2
x^2 + 36 = 100
x^2 = 64
x = 8 feet