Question 386020
lnx + ln (x+3) = 1
ln x(x+3) = 1
x(x+3) = e^1
x^2+3x = e^1
x^2+3x-e = 0
x^2+3x-2.7183 = 0
Applying the "quadratic formula" we get:
x= {0.728968371242625, -3.72896837124262}
Throw out the negative solution (extraneous) which leaves us with:
x = 0.729
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Details of quadratic to follow:
.
*[invoke quadratic "x", 1, 3, -2.7183 ]