Question 385999
What is perpendicular to the graph of 2x - 3y = 12 passing through the poin (4,3)
.
First, determine slope of:
2x - 3y = 12 
-3y = -2x + 12 
y = (2/3)x - 4 
slope then is 2/3
.
A line that is perpendicular must have a "negative reciprocal" slope:
(2/3)m = -1
m = -3/2 (new line slope)
along with given point of (4,3) -- plug it into "point-slope" form:
y - y1 = m(x - x1)
y - 3 = (-3/2)(x - 4)
y - 3 = (-3/2)x + 6
y = (-3/2)x + 9  (this is what they're looking for)